For problem number one asks me to find the m<A. So the first step of this problem is to find out what <A≅<D equals (<A= 6y-2 and <D=5y+8). Then the second step of this problem is to just solve for y, which is y=10. The last step of this problem is to replace the letter y in 6y-2 with the number ten so that I can multiply 6 times 10 which would give me 60-2, and my final answer is going to be m<A=58. In conclusion, this is how I solved problem number one.
For problem number two asks me to find the m<G. So the first step of this problem is to find out what <G and <E equals (<G=8x+1 and <E=11x+8). Then the second step of this problem is to solve for x, which is x=9. The last step of this problem is to replace the letter x in 8x+1 with the number nine so that I can multiply 8 times nine which would give me 72+1, and my final answer is going to be m<G=73. In conclusion, this is how I solved problem number two.
For problem number three asks me to find x. So the first step of this problem is to find out what x equals (6x+2x+24=360). Then the second step of this problem is to solve for x which would be 8x+24=360, then I would have to subtract 24 from each side which would leave me with 360-24 that equals 336. The last step of the problem is to divide 336 by 8 which my final answer would be x=42. In conclusion, this is how I solved problem number three.
Sources: Geometry Notes and Geometry Worksheet
Austin Hardy Geometry Blog 